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-16x^2+26x+5=0
a = -16; b = 26; c = +5;
Δ = b2-4ac
Δ = 262-4·(-16)·5
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{249}}{2*-16}=\frac{-26-2\sqrt{249}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{249}}{2*-16}=\frac{-26+2\sqrt{249}}{-32} $
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